Sequences and figurate numbers

Arithmetic sequences

A sequence is an ordered list of numbers, and it is arithmetic when each term changes by the same fixed amount — the common difference dd. Find dd by subtracting any term from the one after it. It can be negative (19,15,11,19, 15, 11, \dots has d=4d = -4) or even zero. The powers of 2 and the Fibonacci numbers are not arithmetic: their differences keep changing.

Terms are named by position: t1t_1 is the first term, and tnt_n is the nnth. In a statement like tn+1=tn+5t_{n+1} = t_n + 5, the +1+1 sits in the subscript so it is about position; the +5+5 is about value — “the next term is 5 more than the current one”.

The nth term

With first term aa and common difference dd:

tn=a+(n1)dt_n = a + (n - 1)d

Two known terms pin down the sequence. If t4=15t_4 = 15 and t10=33t_{10} = 33, the six steps between them cover 3315=1833 - 15 = 18, so d=3d = 3, and working back gives a=6a = 6.

To test whether a number belongs to a sequence, set tnt_n equal to it and solve for nn. Is 90 a term of 7,12,17,7, 12, 17, \dots? Solving 7+(n1)×5=907 + (n-1) \times 5 = 90 gives n1=16.6n - 1 = 16.6, which is not a whole number — so no.

Arithmetic series

A series is what you get by adding the terms of a sequence. Young Gauss famously summed 1 to 100 by pairing opposite ends — 1+1001 + 100, 2+992 + 99, and so on — giving 50 pairs of 101, or 5050. The same pairing idea gives the general formulas, where \ell is the last term being added:

Sn=n2(a+)=n2(2a+(n1)d)S_n = \frac{n}{2}(a + \ell) = \frac{n}{2}\left(2a + (n-1)d\right)

Example: 5+10+15++1005 + 10 + 15 + \dots + 100 has 20 terms, so S20=202(5+100)=1050S_{20} = \frac{20}{2}(5 + 100) = 1050.

Figurate numbers

Adding more and more terms of simple arithmetic sequences builds the figurate numbers — numbers you can draw as dot patterns:

  • Triangular: Tn=1+2++n=n(n+1)2T_n = 1 + 2 + \dots + n = \frac{n(n+1)}{2}
  • Square: Qn=1+3+5++(2n1)=n2Q_n = 1 + 3 + 5 + \dots + (2n-1) = n^2 — the sum of the first nn odd numbers
  • Pentagonal: Pn=1+4+7+=n(3n1)2P_n = 1 + 4 + 7 + \dots = \frac{n(3n-1)}{2}

The underlying common differences are 1, 2 and 3 respectively.

Proving identities

Exams ask you to show facts like Qn=Tn+Tn1Q_n = T_n + T_{n-1} or Qn=2TnnQ_n = 2T_n - n. Start from one side, substitute the formulas, and simplify step by step until it equals the other side — never start by assuming both sides are equal. A dot diagram (splitting a square into two triangles) often earns the “show that” mark alongside the algebra.